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@@ -1133,6 +1133,7 @@ static void sort_ops(struct keyinfo hash[], char *filename[], struct op *op[])
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}
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}
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+static unsigned int dep_count;
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static void add_dependency(void *ctx,
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struct op *op[],
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char *filename[],
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@@ -1195,6 +1196,8 @@ static void add_dependency(void *ctx,
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pre->file = satisfies_file;
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pre->op = satisfies_opnum;
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list_add(&op[needs_file][needs_opnum].pre, &pre->list);
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+
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+ dep_count++;
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}
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#if TRAVERSALS_TAKE_TRANSACTION_LOCK
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@@ -1251,15 +1254,55 @@ static void make_traverse_depends(char *filename[],
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dep[i-1].file, dep[i-1].op->trav->end);
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}
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talloc_free(dep);
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+ printf("Dep count after traverses: %u\n", dep_count);
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}
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#endif /* TRAVERSALS_TAKE_TRANSACTION_LOCK */
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+static bool changes_db(const struct op *op)
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+{
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+ return gives(op, NULL) != NULL;
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+}
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+
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+static void depend_on_previous(struct op *op[],
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+ char *filename[],
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+ unsigned int num,
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+ struct key_user user[],
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+ unsigned int i,
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+ int prev)
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+{
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+ bool deps[num];
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+ int j;
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+
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+ if (i == 0)
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+ return;
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+
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+ if (prev == i - 1) {
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+ /* Just depend on previous. */
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+ add_dependency(NULL, op, filename,
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+ user[i].file, user[i].op_num,
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+ user[prev].file, user[prev].op_num);
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+ return;
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+ }
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+
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+ /* We have to wait for the readers. Find last one in *each* file. */
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+ memset(deps, 0, sizeof(deps));
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+ deps[user[i].file] = true;
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+ for (j = i - 1; j > prev; j--) {
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+ if (!deps[user[j].file]) {
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+ add_dependency(NULL, op, filename,
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+ user[i].file, user[i].op_num,
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+ user[j].file, user[j].op_num);
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+ deps[user[j].file] = true;
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+ }
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+ }
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+}
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+
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static void derive_dependencies(char *filename[],
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struct op *op[], unsigned int num_ops[],
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unsigned int num)
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{
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struct keyinfo *hash;
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- unsigned int i, j;
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+ unsigned int h, i;
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/* Create hash table for faster key lookup. */
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hash = hash_ops(op, num_ops, num);
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@@ -1267,17 +1310,35 @@ static void derive_dependencies(char *filename[],
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/* Now handle the hard cases: same serial number. */
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sort_ops(hash, filename, op);
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- /* We make the naive assumption that two ops on the same key
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- * have to be ordered; it's overkill. */
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- for (i = 0; i < total_keys * 2; i++) {
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- for (j = 1; j < hash[i].num_users; j++) {
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- add_dependency(hash, op, filename,
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- hash[i].user[j].file,
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- hash[i].user[j].op_num,
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- hash[i].user[j-1].file,
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- hash[i].user[j-1].op_num);
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+ /* Create dependencies back to the last change, rather than
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+ * creating false dependencies by naively making each one
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+ * depend on the previous. This has two purposes: it makes
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+ * later optimization simpler, and it also avoids deadlock with
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+ * same sequence number ops inside traversals (if one
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+ * traversal doesn't write anything, two ops can have the same
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+ * sequence number yet we can create a traversal dependency
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+ * the other way). */
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+ for (h = 0; h < total_keys * 2; h++) {
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+ int prev = -1;
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+
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+ if (hash[h].num_users < 2)
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+ continue;
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+
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+ for (i = 0; i < hash[h].num_users; i++) {
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+ if (changes_db(&op[hash[h].user[i].file]
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+ [hash[h].user[i].op_num])) {
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+ depend_on_previous(op, filename, num,
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+ hash[h].user, i, prev);
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+ prev = i;
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+ } else if (prev >= 0)
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+ add_dependency(hash, op, filename,
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+ hash[h].user[i].file,
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+ hash[h].user[i].op_num,
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+ hash[h].user[prev].file,
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+ hash[h].user[prev].op_num);
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}
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}
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+ printf("Dep count after deriving: %u\n", dep_count);
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#if TRAVERSALS_TAKE_TRANSACTION_LOCK
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make_traverse_depends(filename, op, num_ops, num);
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